Optimal. Leaf size=100 \[ -\frac{4 \sin (a+b x)}{21 b d^3 (d \cos (a+b x))^{3/2}}-\frac{4 \sqrt{\cos (a+b x)} F\left (\left .\frac{1}{2} (a+b x)\right |2\right )}{21 b d^4 \sqrt{d \cos (a+b x)}}+\frac{2 \sin (a+b x)}{7 b d (d \cos (a+b x))^{7/2}} \]
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Rubi [A] time = 0.0819411, antiderivative size = 100, normalized size of antiderivative = 1., number of steps used = 4, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {2566, 2636, 2642, 2641} \[ -\frac{4 \sin (a+b x)}{21 b d^3 (d \cos (a+b x))^{3/2}}-\frac{4 \sqrt{\cos (a+b x)} F\left (\left .\frac{1}{2} (a+b x)\right |2\right )}{21 b d^4 \sqrt{d \cos (a+b x)}}+\frac{2 \sin (a+b x)}{7 b d (d \cos (a+b x))^{7/2}} \]
Antiderivative was successfully verified.
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Rule 2566
Rule 2636
Rule 2642
Rule 2641
Rubi steps
\begin{align*} \int \frac{\sin ^2(a+b x)}{(d \cos (a+b x))^{9/2}} \, dx &=\frac{2 \sin (a+b x)}{7 b d (d \cos (a+b x))^{7/2}}-\frac{2 \int \frac{1}{(d \cos (a+b x))^{5/2}} \, dx}{7 d^2}\\ &=\frac{2 \sin (a+b x)}{7 b d (d \cos (a+b x))^{7/2}}-\frac{4 \sin (a+b x)}{21 b d^3 (d \cos (a+b x))^{3/2}}-\frac{2 \int \frac{1}{\sqrt{d \cos (a+b x)}} \, dx}{21 d^4}\\ &=\frac{2 \sin (a+b x)}{7 b d (d \cos (a+b x))^{7/2}}-\frac{4 \sin (a+b x)}{21 b d^3 (d \cos (a+b x))^{3/2}}-\frac{\left (2 \sqrt{\cos (a+b x)}\right ) \int \frac{1}{\sqrt{\cos (a+b x)}} \, dx}{21 d^4 \sqrt{d \cos (a+b x)}}\\ &=-\frac{4 \sqrt{\cos (a+b x)} F\left (\left .\frac{1}{2} (a+b x)\right |2\right )}{21 b d^4 \sqrt{d \cos (a+b x)}}+\frac{2 \sin (a+b x)}{7 b d (d \cos (a+b x))^{7/2}}-\frac{4 \sin (a+b x)}{21 b d^3 (d \cos (a+b x))^{3/2}}\\ \end{align*}
Mathematica [C] time = 0.0641523, size = 59, normalized size = 0.59 \[ \frac{\sin ^3(2 (a+b x)) \cos ^2(a+b x)^{3/4} \, _2F_1\left (\frac{3}{2},\frac{11}{4};\frac{5}{2};\sin ^2(a+b x)\right )}{24 b (d \cos (a+b x))^{9/2}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.068, size = 396, normalized size = 4. \begin{align*}{\frac{4}{21\,{d}^{4}b} \left ( -8\,\sqrt{ \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}}\sqrt{2\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1}{\it EllipticF} \left ( \cos \left ( 1/2\,bx+a/2 \right ) ,\sqrt{2} \right ) \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{6}+12\,\sqrt{ \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}}\sqrt{2\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1}{\it EllipticF} \left ( \cos \left ( 1/2\,bx+a/2 \right ) ,\sqrt{2} \right ) \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{4}-8\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{6}\cos \left ( 1/2\,bx+a/2 \right ) -6\,\sqrt{ \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}}\sqrt{2\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1}{\it EllipticF} \left ( \cos \left ( 1/2\,bx+a/2 \right ) ,\sqrt{2} \right ) \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}+8\,\cos \left ( 1/2\,bx+a/2 \right ) \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{4}+\sqrt{ \left ( \sin \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) \right ) ^{2}}\sqrt{2\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1}{\it EllipticF} \left ( \cos \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) ,\sqrt{2} \right ) + \left ( \sin \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) \right ) ^{2}\cos \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) \right ) \sqrt{d \left ( 2\, \left ( \cos \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1 \right ) \left ( \sin \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) \right ) ^{2}}{\frac{1}{\sqrt{-d \left ( 2\, \left ( \sin \left ( 1/2\,bx+a/2 \right ) \right ) ^{4}- \left ( \sin \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) \right ) ^{2} \right ) }}} \left ( 2\, \left ( \cos \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1 \right ) ^{-3} \left ( \sin \left ({\frac{bx}{2}}+{\frac{a}{2}} \right ) \right ) ^{-1}{\frac{1}{\sqrt{d \left ( 2\, \left ( \cos \left ( 1/2\,bx+a/2 \right ) \right ) ^{2}-1 \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sin \left (b x + a\right )^{2}}{\left (d \cos \left (b x + a\right )\right )^{\frac{9}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (-\frac{\sqrt{d \cos \left (b x + a\right )}{\left (\cos \left (b x + a\right )^{2} - 1\right )}}{d^{5} \cos \left (b x + a\right )^{5}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sin \left (b x + a\right )^{2}}{\left (d \cos \left (b x + a\right )\right )^{\frac{9}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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